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Question

The stopping potential in a photoelectric experiment is linearly related to the inverse of the wavelength (1/λ) of the light falling on the cathode. The potential difference applied across an X-ray tube is linearly related to the inverse of the cutoff wavelength (1/λ) of the X-ray emitted. Show that the slopes of the lines in the two cases are equal and find its value.

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Solution

V0 - Stopping Potential
K - Potential difference across X-ray tube
λ - Wavelength
λ - Cut difference Wavelength
eV0=hf-hf0λ=hceVeV0=hcλor =hceor V0λ=hce
Here, the slopes are same.
i.e. V0λ = Vλ
hce=6.63×10-34×3×1081.6×10-19=1.242×10-6 Vm

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