The straight line joining the vertex of an isosceles triangle to any point in the base is smaller than either of the equal sides of the triangle.
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Solution
Let ABC be the triangle and BC is its base. Let AD be the line joining A to BC Given ABC is an isosceles triangle hence line joining the vertex to any point on its base is 90o Here △ABD and △ADC are right angled triangles Here AB and AC are the hypotenuses of △ABD and △ADC We know that hypotenuse is greater than any of the sides of triangle Hence AB>AD and also AC>AD