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Question

The straight line y=x−2 rotates about a point where it cuts the x−axis and becomes perpendicular to the straight line ax+by+c=0. Then its equation is

A
ax+by+2a=0
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B
axby2a=0
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C
bx+ay2b=0
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D
aybx+2b=0
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Solution

The correct option is D aybx+2b=0
Given eq y=x2
Slope of new line after rotation is m=ba
Since it is perpendicualr to ax+by+c=0
And it cuts x-axis at (2,0)
Equation of line from (2,0) and slope ba
y=ba(x2)
ay=bx2b
aybx+2b=0

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