The straight lines I1,I2,I3 are parallel and lie in the same plane. A total number of m points on I1; n points on I2; k points on I3, the maximum number of triangles formed with vertices at these points are
A
m+n+kC3
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B
m+n+kC3−mC3−nC3−kC3
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C
mC3+nC3+kC3
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D
None of these
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Solution
The correct option is Cm+n+kC3−mC3−nC3−kC3 Toatl number of points are m+n+k the Δ′s formed by these points =m+n+kC3 Points on the same line gives no triangle Such Δ′s are mC3+nC3+kC3 Therefore required number =m+n+kC3−mC3−nC3−kC3