The straight lines l2||l2||l3 lies in the same plane. A total of m points are taken on l1,n points on l2 and k points on l3, then the maximum number of triangles formed with vertices at these points are
A
m+n+kC3−(mC3+nC3+kC3)
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B
mC3+nC3+kC3
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C
m+n+kC3
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D
None of these
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Solution
The correct option is Am+n+kC3−(mC3+nC3+kC3) Total Number of points =m+n+k ∴ Number of Δ's formed =m+n+kc3 Now m,n,k are lies on the lines l1,l2,l3 respectively means these are collinear points for the line l1,l2,l3 respectively these point do not form any triangle. ∴ Number of dummy triangle mC3,nC3,kC3 ∴ actual number of triangle =m+n+kC3−(mC3+nC3+kC3)