The straight lines represented by the equation $a x^{2} + 2 b x y + b y^{2} = 0$ are perpendicular if

a-b = 0

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a+b = 0

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a+2h+b = 0

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a = 2h

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Solution

The correct option is B
a+b = 0

The angle between the straight lines $a x^{2} + 2 b x y + b y^{2} = 0$ is given by

$tan θ = ∣ ∣ ∣ \frac{2 \sqrt{h^{2} - a b}}{a + b} ∣ ∣ ∣$

They will be perpendicular if a+b = 0

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