wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The streets of a city are arranged like the lines of a chess board. There are 5 streets running North to South and 3 streets running East to West. The number of ways in which a man can travel from NW to SE corner going the shortest possible distance is:

A
6!4!2!
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
56
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8!5!3!
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A 6!4!2!
D 15
Here we should go (31) steps to east and (51) steps to south.

So the total steps we should go=5+32 ways

Hence the total number of ways = 5+32C51.31C31
=6C4.2C2
=6!4!2! (2C2=1)
=6×5×4!4!2!=6×52=15 ways.

Option (a) and (d) are correct.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon