The strength (in $g / L$ ) of $10$ volume of $H_{2} O_{2}$ solution is:

10

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68

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60.70

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30.36

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Solution

The correct option is D $30.36$
$10$ volume $H_{2} O_{2}$ means, $1$ litre of $H_{2} O_{2}$ will give $10$ litre oxygen at STP.

$2 H_{2} O_{2} 68 \to 2 H_{2} O + O_{2} 22.4 L a t S T P$

$∵ 22.4 L O_{2}$ is obtained at STP from $68 g H_{2} O_{2}$

$∴ 10 L O_{2}$ is obtained at STP from $\frac{68}{22.4} \times 10 g H_{2} O_{2}$ $= 30.36 g$

Thus, strength of $H_{2} O_{2} = 30.36 g / L$ .

Hence, option $D$ is correct.

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The strength in volumes of a solution containing 30.36 $g m l i t r e^{- 1}$ of $H_{2} O_{2}$ is

The strength in volumes of a solution containing 30.36 g/litre of $H_{2} O_{2}$ is

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\frac{N}{0.56}

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