The stress along the length of a rod(with rectangular cross section) is 1% of the Young's modulus of its material. What is the approximate percentage of change of its volume? (Poisson's ratio of the material of the rod is 0.3).
A
3%
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B
1%
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C
0.7%
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D
0.4%
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Solution
The correct option is D0.4% ⇒v=xyz dvv=dxx+dyy+dzz=dll−μdll−μdll=(1−2μ)dll Stress =Y×strain 0.01Y=Ydll⇒dll=0.01 dvv=0.01×(1−0.6)=0.01×0.4 % Volume change =0.4%.