The stress required to double the length of a wire of Young's modulus $E$ is :

2 E

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E

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E / 2

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3 E

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Solution

The correct option is B $E$
Young's modulus, $E$ $= \frac{s t r e s s}{s t r a i n}$
Where, $s t r a i n = \frac{c h a n g e i n l e n g t h}{o r i g i n a l l e n g t h}$
Let the initial length of the wire be $x$ m.
Thus change in length = $2 x - x = x$
Original length = $x$
So, strain = 1
So, we get $E$ = stress/1

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Similar questions

20 \times 10^{8} {N m}^{- 2}

ρ

List - I	List - I
A. Volumetric strain	1. $2 (1 + μ)$
B. Strain energy per unit volume	2. $3 (1 - 2 μ)$
C. Ratio of Young's modulus to bulk modulus	3. $\frac{ρ}{E} (1 - 2 μ)$
D. Ratio of Young's modulus to modulus of	4. $\frac{ρ}{2 E}$
	5. $2 (1 - μ)$

A B C D

20 \times 10^{8} N / m^{2}

N / m^{2},

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