The string AB vibrates in two loops with a tuning fork when block hangs in air. Now block is completely immersed in water, the string vibrates in three loops with same tuning fork.
The specific gravity of block is :

1.2

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1.8

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2

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\frac{5}{9}

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Solution

The correct option is B $1.8$
$\frac{T_{1}}{T_{2}} = \frac{(3)^{2}}{(2)^{2}} = \frac{9}{4}$ , $T_{2} = T_{1} - B \Rightarrow B = T_{1} - T_{2}$
specific gravity of block = $\frac{w t . i n a i r}{l o s s i n w t . i n w a t e r} = \frac{T_{1}}{T_{1} - T_{2}}$

$= \frac{1}{1 - \frac{T_{2}}{T_{1}}} = \frac{1}{1 - \frac{4}{9}} = \frac{9}{5} = 1.8$

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The string AB vibrates in two loops with a tuning fork when block hangs in air. Now block is completely immersed in water, the string vibrates in three loops with same tuning fork.The specific gravity of block is :

The correct option is B 1.8T1T2=(3)2(2)2=94, T2=T1−B⇒B=T1−T2specific gravity of block =wt.inairlossinwt.inwater=T1T1−T2 =11−T2T1=11−49=95=1.8

The string AB vibrates in two loops with a tuning fork when block hangs in air. Now block is completely immersed in water, the string vibrates in three loops with same tuning fork.
The specific gravity of block is :