Question

The string of a kite is 150 m long and it makes an angle of ${60}^0$ with the horizontal. Find the height of the kite from the ground.

Answer 1

Let $h$ be the of height kite.

As we know that,

$\sin \theta =\frac{\text{Perpendicular}}{\text{Hypotenuse}}$

Now, in $△ABP$

$\sin 60°=\frac{AB}{AP}$

$\Rightarrow \frac{\sqrt{3}}{2}=\frac{h}{150}$

$\Rightarrow h=\frac{\sqrt{3}}{2}\times 150=75\sqrt{3}m$

Hence the height of the kite is $75\sqrt{3}m$.