Question

The string of a violin emits a note of $205$ Hz at its correct tension. The string is tightened slightly and then it produces six beats in 2 seconds with tuning fork of the frequency 205Hz. The frequency of the note emitted by the taut string is

Answer 1

As $V\alpha \sqrt{T}$ , therefore the frequency of vibration of the string increases.

As it gives 6 beats per 2 sec, i.e 205 Hz. hence the frequency of taut string would be $205+3=208Hz$

i.e equal to $205+6=211Hz$