The string of kite is 100m- long and it makes an angle of 60 - with the horizontal Find the height of kite- assuming that there is no slack in the string-

REF.Image sin (θ )=opposite sidehypotenuse sin 60=BCAC=h100 √(3)2=h100 #160; #160; (∵ sin 60=√(3)2) h=50√(3)m ...

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Standard XII

Mathematics

Trigonometric Ratios of Compound Angles

The string of...

Question

The string of kite is $100$ m, long and it makes an angle of $60^{\circ}$ with the horizontal Find the height of kite, assuming that there is no slack in the string.

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Solution

REF.Image

$s i n (θ) = \frac{o p p o s i t e s i d e}{h y p o t e n u s e}$

$s i n 60 = \frac{B C}{A C} = \frac{h}{100}$

$\frac{\sqrt{3}}{2} = \frac{h}{100}$ $(∵ s i n 60 = \frac{\sqrt{3}}{2})$

$h = 50 \sqrt{3} m$

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The string of kite is 100m, long and it makes an angle of 60∘ with the horizontal Find the height of kite, assuming that there is no slack in the string.

REF.Imagesin(θ)=oppositesidehypotenusesin60=BCAC=h100√32=h100 (∵sin60=√32)h=50√3m

The string of kite is $100$ m, long and it makes an angle of $60^{\circ}$ with the horizontal Find the height of kite, assuming that there is no slack in the string.

REF.Image

$s i n (θ) = \frac{o p p o s i t e s i d e}{h y p o t e n u s e}$

$s i n 60 = \frac{B C}{A C} = \frac{h}{100}$

$\frac{\sqrt{3}}{2} = \frac{h}{100}$ $(∵ s i n 60 = \frac{\sqrt{3}}{2})$

$h = 50 \sqrt{3} m$