The string of pendulum of length $l$ is displaced through $90^{o}$ from the verticle and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

m g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 m g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 m g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 m g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $3 m g$
$T = m g + \frac{m v^{2}}{l} = m g + 2 m g = 3 m g$
where $v = \sqrt{2 g l}$ from $\frac{1}{2} m v^{2} = m g l$

Suggest Corrections

Similar questions

Q. The string of a pendulum of length

l

is displaced through

90^{\circ}

from the vertical and released. Then the minimum strength of the string in order to withstand the tension as the pendulum passes through the mean position is:

The string of pendulum of length I is displaced through $90^{\circ}$ from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

Q. A pendulum string of length

l

is moved upto a horizontal position and released as shown in figure. If the mass of pendulum is

m

, then what is the minimum strength of the string that can withstand the tension as the pendulum passes through the position of equilibrium?
(neglect mass of the string and air resistance)

Q. A simple pendulum oscillates in a vertical plane. When it passes through the mean position, the tension in the string is 3 times the weight of the pendulum bob. What is the maximum displacement of the string of the pendulum with respect to the verticle.

Q. A simple pendulum oscillates in a vertical plane. When it passes through the mean position, the tension in the string is 3 times the weight of the pendulum bob. What is the maximum angular displacement of the pendulum of the string with respect to the downward vertical.

Join BYJU'S Learning Program

The string of pendulum of length l is displaced through 90o from the verticle and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

The correct option is B 3mgT=mg+mv2l=mg+2mg=3mgwhere v=√2gl from 12mv2=mgl

The string of pendulum of length $l$ is displaced through $90^{o}$ from the verticle and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

The correct option is B $3 m g$
$T = m g + \frac{m v^{2}}{l} = m g + 2 m g = 3 m g$
where $v = \sqrt{2 g l}$ from $\frac{1}{2} m v^{2} = m g l$