Question

The structural formula of a compound is $C{H}_3-CH=C=C{H}_2.$ The type of hybridisation at the four carbons from left to right are:

• A. $s{p}^3,sp,s{p}^2,s{p}^3$
• B. $s{p}^2,s{p}^3,s{p}^2,sp$
• C. $s{p}^3,s{p}^2,sp,s{p}^2$
• D. $s{p}^3,s{p}^2,s{p}^2,s{p}^2$

Answer 1

The correct option is C $s{p}^3,s{p}^2,sp,s{p}^2$

The hybridization of carbon in any compound is based on the no. of pi bonds attached to the given carbon. If carbon has only sigma bonds, then hybridization is $s{p}^3$, if carbon forms one pi bond, then $s{p}^2$ hybridized, and if carbon forms $2$ pi bonds, then, it is $sp$ hybridized.

Hence the correct order is $s{p}^3,s{p}^2,sp,s{p}^2$