The structural formula of iso-butene is:

C H_{3} C H_{2} C H = C H_{2}

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C H_{3} C H = C H - C H_{3}

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\begin{matrix} C H_{3} & - & C H & - & C H_{3} | C H_{3} \end{matrix}

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\begin{matrix} C H_{2} & = & C & - & C H_{3} | C H_{3} \end{matrix}

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Solution

The correct option is C $\begin{matrix} C H_{2} & = & C & - & C H_{3} | C H_{3} \end{matrix}$
The structural formula of Isobutene is-

$C H_{2} = C | C H_{3} - C H_{3}$

So, the correct option is $D$

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Similar questions

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

C H_{3} - C H_{3} | C | C H_{3} - C H_{3} (N e o - p e n t a n e)

C H_{3} - C H | C H_{3} - C H_{2} - C H_{3} (I s o - p e n t a n e)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{3} (n - p e n t a n e)

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

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