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B
Trigonal bipyramidal and sp3drespectively.
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C
Trigonal and sp2respectively.
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D
Square bipyramidal and sp3d2respectively.
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Solution
The correct option is ASquare pyramidal and sp3d2respectively. Frist try and decude the Lewis structure of BrF5. You will see that the steric number of the central Bromine atom is = 5 bond pairs + one lone pair = 6. Hence the shape is square pyramidal structure and the hybridisation is sp3d2.