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B
Trigonal bipyramidal and respectively.
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C
Trigonal and respectively.
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D
Square bipyramidal and respectively.
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Solution
The correct option is ASquare pyramidal and respectively. Frist try and decude the Lewis structure of BrF5. You will see that the steric number of the central Bromine atom is = 5 bond pairs + one lone pair = 6. Hence the shape is square pyramidal structure and the hybridisation is sp3d2.