The structure and hybridization of $S i (C H_{3})_{4}$ respectively, is:

bent and

s p

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trigonal and

s p^{2}

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octahedral and

s p^{3} d

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tetrahedral and

s p^{3}

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Solution

The correct option is C tetrahedral and $s p^{3}$
The structure and hybridization of $S i (C H_{3})_{4}$ is tetrahedral and $s p^{3} -$ hybridisation because $S i$ forms $4$ bond pairs.

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Similar questions

The structure and hybridization of $S i (C H_{3})_{4}$ is:

The structure and hybridization of Si $(C H_{3})_{4}$ is:

S i (C H_{3})_{4}

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

N {(S i H_{3})}_{3}

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