In highly acidic medium, the given tripeptide exists as cationic form.
Net charge +2
|Z1| = 2 at pH = 2
(ii) At pH = 6 (isoelectric point)
At isoelectric point, the given tripeptide exists as Zwitter ion.
net charge = 0
|Z2| = 0 at pH = 6
(iii) At pH = 11 (basic medium)
In basic medium the given tripeptide exists in anionic form.
Net charge = –3
|Z3| = 3
Therefore, |Z1| + |Z2| + |Z3| = 2 + 0 + 3 = 5