The structure of the complex $[P t (N H_{3})_{4}]^{2 +}$ is:

Square planar

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Tetrahedral

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Pyramidal

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Pentagonal

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Solution

The correct option is A Square planar
$[P t (N H_{3})_{4}]^{2 +} Valence shell electronic configuration of P t^{2 +} \to [X e] 4 f^{14} 5 d^{8} 6 s^{0} 6 p^{0}$

$N H_{3}$ is a strong field ligand. So all unpaired electrons get paired.

$Hybridisation = d s p^{2} Structure = Square planar$

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