The structure of the complex $[P t (N H_{3})_{4}]^{2 +}$ is

Pyramidal

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Pentagonal

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Square planar

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Tetrahedral

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Solution

The correct option is C Square planar
$5 d^{8}$ configuration have higher CFSE and then the pairing of electron takes place against the Hund's rule.
G.S Electronic configuration of $P t^{2 +} - [X e] 4 f^{14} 5 d^{8}$

The hybridiastion of the complex is $d s p^{2}$ and the structure is thus square planar.

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[P t (N H_{3})_{4}]^{2 +} [C o (S C N)_{4}]^{2 -} [C u (e n)_{2}]^{2 +} [H g I_{4}]^{2 -}

[P t (N H_{3})_{4}]^{2 +}

The complex $[P t (N H_{3})_{4}]^{2 +}$ has ______ structure:

[P t (N H_{3})_{4}]^{2 +}

[P t {(N H_{3})}_{4}] [P t C l_{6}]

[P t {(N H_{3})}_{4} C l_{2}] [P t C l_{4}]

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