The structure of the third member of the alkyne series is:

H - C \equiv C - H

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H - C \equiv C - C H_{3}

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H - C \equiv C - C H_{2} C H_{3}

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H - C \equiv C - C \equiv C - H

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H - C - C - C H = C - H_{2}

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Solution

The correct option is E $H - C \equiv C - C H_{2} C H_{3}$
Alkyne has the general molecular formula $C_{n} H_{2 n}$
and alkyne group start from $C_{2} H_{2}$ .
Thus third member will have 4 carbon atom and it will be given as follow:
$H - C \equiv C - C H_{2} C H_{3}$

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