The substance A, when dissolved in solvent B, shows the molecular mass corresponding to $A_{3}$ . The Vant Hoff's factor will be:

1

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2

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3

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1 / 3

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Solution

The correct option is A $1 / 3$
Let us consider the formula of vant hoff factor ,
$i = \frac{n o r m a l m o l e c u l a r w e i g h t}{o b s e r v e d m o l e c u l a r w e i g h t}$
Let $A$ be $x g m o l^{- 1}$ of normal molecular weight
Therefore, Observed molecular weight becomes $3 x g m o l^{- 1}$ as molecule of $A$ becomes $A_{3}$
Hence,
$i = \frac{x}{3 x} = \frac{1}{3}$

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