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Question

The substitution required to change (3y7x+7)dx+(7y3x+3)dy=0 to a homogeneous differential equation is

A
x=X+1,y=Y
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B
x=X,y=Y+1
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C
x=X+1,y=Y+1
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D
x=X+2,y=Y+2
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Solution

The correct option is B x=X+1,y=Y
Let x=X+h and y=Y+K
3(Y+K)7(X+h)+7=3Y7X
3K7h+7=0
7h3K=7-------------(1)
7(Y+K)3(X+h)+3=3X+7Y
3=3h7K-----------------(2)
(7h3k=7)×3
(3h7k=3)×7
------------------------------------------
40k=0k=0
------------------------------------------
h=1
x=X+1;y=Y+0=Y

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