The subtangent at any point of the curve xmyn=am+n varies as
A
(abscissa)2
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B
(abscissa)3
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C
abscissa
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D
ordinate
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Solution
The correct option is D abscissa We have, xmyn=am+n Taking logarithm on both sides, we get ⇒mlogx+nlogy=(m+n)loga Differentiating both sides w.r.t. x, we get ∴mx+nydydx=0 ⇒dxdy=−nxmy ∴ Subtangent =∣∣ydxdy∣∣=nxm∝x