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Question

The subtangent at any point on the curve xmyn=am+n varies as.

A
(abscissa)2
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B
(ordinate)2
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C
Abscissa
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D
Ordinate
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Solution

The correct option is A Abscissa
We have,
xmyn=am+n
mlogeX+nlogey=(m+n)logea
On differentiating both sides w.r.t. x, we get
mx+nydydx=0
dydx=mynx
Therefore, length of the subtangent =ydy/dx
=y×nxmy
=nm|x|x

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