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Trends in Modern Periodic Table

The successiv...

Question

The successive ionization energies for element X is given below IE : 250kJmol II: 820kJmol 1100kJmol 1400kJmol Find out the number of valence electrons for the element X.

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I E_{1}

250 k J m o l^{- 1}

I E_{2}

820 k J m o l^{- 1}

I E_{3}

1100 k J m o l^{- 1}

I E_{4}

1400 k J m o l^{- 1}

X

I E_{1} = 250 {kJ mol}^{- 1}

I E_{2} = 820 {kJ mol}^{- 1}

I E_{3} = 1100 {kJ mol}^{- 1}

I E_{4} = 1400 {kJ mol}^{- 1}

X

X

I E_{1} = 250 {kJ mol}^{- 1}

I E_{2} = 820 {kJ mol}^{- 1}

I E_{3} = 1100 {kJ mol}^{- 1}

I E_{4} = 1400 {kJ mol}^{- 1}

X

(X)

I_{1}, I_{2}, I_{3}, I_{4}

I_{5}

800, 2427, 3658, 25024, 32824 {kJ mol}^{- 1}

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