The sulfate of calcium has a formula $C a S O_{4}$ . The formula of the sulphate of ammonium will be:

N H_{3} S O_{4}

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(N H_{3})_{2} S O_{4}

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N H_{4} S O_{4}

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(N H_{4})_{2} S O_{4}

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Solution

The correct option is D $(N H_{4})_{2} S O_{4}$
Sulphate ion is bivalent anion (i.e. charge is -2) and is represented as $S O_{4}^{- 2}$ and calcium ion is bivalent cation $C a^{+ 2}$ and by Crisscross method their formula is $C a S O_{4}$ .Now ammonium is univalent cation given by $N H_{4}^{+}$ and hence by Crisscross method we get sulphate of ammonium formula as $(N H_{4})_{2} S O_{4}$ .

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