The sulphuric acid solution present in three different beakers in the lab is given below.

Beaker A $2 L 324 m l$

Beaker B $1.585 L$

Beaker C $0.878 L$

Evaluate the following expression.

(Volume of sulphuric acid in beaker B $+$ Volume of sulphuric acid in beaker C) $-$ Volume of sulphuric acid in beaker A

139 m L

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0.139 L

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Both A and C

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1.139 L

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Solution

The correct option is C Both A and C
Volume of sulphuric acid in beaker B $= 1.585 L$
Volume of sulphuric acid in beaker C $= 0.878 L$
Volume of sulphuric acid in beaker A $= 2 L 324 m L$
$= 2.324 L$
Expression $= (1.585 + 0.878) - 2.324$
In the first step, we will solve the bracket of $(1.585 + 0.878) .$
$1.585 + 0.878 = 2.463 L$
The next step is to subtract $2.324$ from $2.463$
$= 2.463 - 2.324$
$= 0.139 L$
So, option A is correct.
$0.139 L$ is also $0.139 \times 1000 = 139 m L$
So, option C is also correct.

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