The sulphuric acid solution present in three different beakers in the lab is given below.
Beaker A
2L324ml
Beaker B
1.585L
Beaker C
0.878L
Evaluate the following expression.
(Volume of sulphuric acid in beaker B + Volume of sulphuric acid in beaker C) − Volume of sulphuric acid in beaker A
A
1.139L
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B
139mL
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C
0.139L
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D
Both A and C
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Solution
The correct option is D Both A and C Volume of sulphuric acid in beaker B =1.585L
Volume of sulphuric acid in beaker C =0.878L
Volume of sulphuric acid in beaker A =2L324mL =2.324L
Expression =(1.585+0.878)−2.324
In the first step, we will solve the bracket of (1.585+0.878). 1.585+0.878=2.463L
The next step is to subtract 2.324 from 2.463 =2.463−2.324 =0.139L
So, option A is correct. 0.139L is also 0.139×1000=139mL
So, option C is also correct.