The sum and product of the zeros of a quadratic polynomial are 3 and −10 respectively. The quadratic polynomial is

(a) x² − 3x + 10
(b) x² + 3x −10
(c) x² − 3x −10
(d) x² + 3x + 10

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Solution

$(c) x^{2} - 3 x - 10 Given: Sum of zeroes, α+β = 3 Also, product of zeroes, αβ=-10 ∴ Required polynomial = x^{2} - (α+β) + αβ = x^{2} - 3 x - 10$

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Similar questions

The sum and the product of the zeros of a quadratic polynomial are 3 and -10 respectively. The quadratic polynomial is

(a) $x^{2} - 3 x + 10$ (b) $x^{2} + 3 x - 10$ (c) $x^{2} - 3 x - 10$ (d) $x^{2} + 3 x + 10$

x^{2} - 3 x + 10 = 0

x^{2} - 3 x - 10 = 0

x^{2} + 3 x - 10 = 0

x^{2} + 3 x + 10 = 0

Common factor in quadratic polynomials $x^{2} + 8 x + 15$ and $x^{2} + 3 x - 10$ is

x^{2} - 3 x - 5

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