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Question

The sum mean and variance of a B.D. for 5 trials is 1.8, then the Binomial distribution (B.D.) is given by

A
(0.2+0.8)5
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B
(0.3+0.7)5
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C
(0.4+0.6)5
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D
None of these
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Solution

The correct option is A (0.2+0.8)5
mean(m) for B.D.=np
Variance (o2) for B.D.=npq
np(1+q)=1810,p(1+q)=1850
(1q)(1+q)=1850
q=0.8(q=0.8 can't possible as 0q1)
q=0.8,p=0.2
B.D.=(0.2+.8)5

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