The sum of $11 x^{2} - 8 x + 4$ and $6 x^{2} + 7 x - 10$ is

17 x^{2} + x - 6

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17 x^{2} - x - 6

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17 x^{2} - x + 6

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17 x^{2} + x + 6

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Solution

The correct option is B $17 x^{2} - x - 6$
$11 x^{2} - 8 x + 4$
$6 x^{2} + 7 x - 10 - -------------- -$
$17 x^{2} - x - 6$

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Similar questions

Tick $(✓)$ the correct answer in each of the following:
$(2 x + 3) (3 x - 1) = ?$

(a) $(6 x^{2} + 8 x - 3)$
(b) $(6 x^{2} + 7 x - 3)$
(c) $6 x^{2} - 7 x - 3$
(d) $(6 x^{2} - 7 x + 3)$

Find the quotient and remainder when each of the polynomials below is divided by 2x + 1.

(i)

(ii)

(iii)

(iv)

(v)

(vi)

6 x^{2} + 7 x - 10 = 0

The sum of $11 x^{2} - 8 x + 4$ and $6 x^{2} + 7 x - 10$ is:

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