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Question

The sum of 20 terms of an A.P. whose nth term 4n−1 is :

A
820
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B
79
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C
80n1
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D
80n+1
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Solution

The correct option is A 820
Given, an=4n1 putting n=1,2,3,......
a1=3
a2=7
a3=11
a4=15
Series is 3,7,11,15,......
S20=202{2(3)+(201)4}
=10{6+76}
=10×82
=820

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