The sum of 3 consecutive multiples of 8 is 888. Find the multiples
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Solution
Let 3 consecutive multiple of 8 8x,8(x+1),8(x+2) Sum=8x+8(x+1)+8(x+2)=888 8(x+x+x+1+2)=888 3(x+1)=111 x+1=1113 x+1=37 x=36 First multiple =8x=8×36=288 Second =8(x+1)=8×37=296 Third =8(x+2)=8×38=304