The sum of $3$ consecutive terms is $99$ find the terms

Open in App

Solution

Let the numbers be $x - 1, x, x + 1$
The sum of terms is $x - 1 + x + x + 1 = 99 3 x = 99 x = 33$
The number of terms is $32, 33, 34$

Suggest Corrections

Similar questions

3

69

the sum of four consecutive terms of A.P is 2 .The sum of 3rd and 4th terms is 11. Find the terms

12

3^{r d}

4^{r d}

14

a - d, a, a + d, a + 2 d

Find 3 consecutive terms in GP whose sum is 13 and sum of whose square is 91?

3

27

504

Join BYJU'S Learning Program