The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th,11th,13thelements of the same progression. Then which element of the series should necessarily be equal to zero?
Soln:
The 3rd term will be x+2d
The 15th term will bex+14d
From the information given in the question,
x+2d+x+14d=x+5d+x+10d+x+12d
Solving we get,x+11d=0, this is nothing but the 12th term of the series.