The sum of 3-1- 13 - is

The correct option is B 92 Given series is 3,1, 13,.. Given series is in GP.The common ratio is given as 13 The sum of infinite terms is #160; ...

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Sum of Infinite Terms

The sum of ...

Question

The sum of $3, 1, \frac{1}{3}, . . . .$ is

\frac{5}{2}

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\frac{9}{2}

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\frac{7}{2}

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\frac{11}{2}

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Solution

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1

7^{2}

9^{2}

5^{2}

11^{2}

$1^{2} + 3^{2} + 5^{2} + 7^{2} + 9^{2}$ =___.

\frac{1^{2}}{1} + \frac{5^{2}}{11} + \frac{9^{2}}{11^{2}} + \frac{13^{2}}{11^{3}} + . . . . . . .

1^{2} = \frac{1}{6} [1 \times (1 + 1) \times (2 \times 1 + 1)] 1^{2} + 2^{2} = \frac{1}{6} [2 \times (2 + 1) \times (2 \times 2 + 1)] 1^{2} + 2^{2} + 3^{2} = \frac{1}{6} [3 \times (3 + 1) \times (2 \times 3 + 1)] 1^{2} + 2^{2} + 3^{2} + 4^{2} = \frac{1}{6} [4 \times (4 + 1) \times (2 \times 4 + 1)]

1^{2} + 2^{2} - 3^{2} + 4^{2} + 5^{2} - 6^{2} + 7^{2} + 8^{2} - 9^{2} + . . . .

3 n

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