The sum of $3 a^{2} b$ , $3 a^{2} b$ and $4 a^{2} b$ is

$3 a^{2} b$

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$4 a^{2} b$

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$7 a^{2} b$

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$10 a^{2} b$

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Solution

The correct option is D
$10 a^{2} b$

Addition of like terms results in a single term whose coefficient is equal to the sum of the coefficients of the given terms.

$3 a^{2} b + 3 a^{2} b + 4 a^{2} b$ = $(3 + 3 + 4) a^{2} b$ = $10 a^{2} b$

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