The sum of 5 consecutive numbers is 325. Find the numbers.

Open in App

Solution

Let the 5 consecutive numbers be x - 2, x - 1, x, x + 1, and x + 2.

Hence, their sum = 5x = 325.

Therefore, $x = \frac{325}{5} = 65$ .

So, the numbers are 63, 64, 65, 66 and 67 whose sum will be 325.

Suggest Corrections

Similar questions

Twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178. Thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177. Find the smallest even number.

If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then find the smallest even number.

The sum of 5 consecutive odd numbers is 135. Find the numbers.

Join BYJU'S Learning Program

The sum of 5 consecutive numbers is 325. Find the numbers.

Let the 5 consecutive numbers be x - 2, x - 1, x, x + 1, and x + 2. Hence, their sum = 5x = 325. Therefore, x=3255=65. So, the numbers are 63, 64, 65, 66 and 67 whose sum will be 325.

Let the 5 consecutive numbers be x - 2, x - 1, x, x + 1, and x + 2.

Hence, their sum = 5x = 325.

Therefore, $x = \frac{325}{5} = 65$ .

So, the numbers are 63, 64, 65, 66 and 67 whose sum will be 325.