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Question

The sum of 5th term and 6th term is equal to 0 of the expansion of the term (2a − b)n. The value of a/b is

A
n + 4 10
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B
10 (n 4)
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C
10 (n + 4)
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D
n 4 10
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Solution

The correct option is D n 4 10
T5 = nC4 (2a)(n − 4) (−b)4 T6 = nC5 (2a)(n − 5) (−b)5 =−nC5 (2a)(n − 5) b5 T5 + T6 = 0nC4 (2a)(n − 4) (−b)4 = nC5 (2a)(n − 5) b5 nC4 (2a)= nC5 (b)ab = 12(nC5nC4) = n − 410

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