The sum of 5th term and 6th term is equal to 0 of the expansion of the term (2a−b)n. The value of a/b is
A
n+410
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10(n−4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10(n+4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
n−410
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is Dn−410 T5=nC4(2a)(n−4)(−b)4T6=nC5(2a)(n−5)(−b)5=−nC5(2a)(n−5)b5T5+T6=0nC4(2a)(n−4)(−b)4=nC5(2a)(n−5)b5nC4(2a)=nC5(b)ab=12(nC5nC4)=n−410