The sum of $7$ terms of the series $1^{2} - 2^{2} + 3^{2} - 4^{2} + 5^{2} - 6^{2} + . . .$ is

- 21

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15

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28

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- 35

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Solution

The correct option is C $28$
We can see that first 6 terms taken in pair and is equal to $- 3 + (- 7) + (- 11)$
So the sum will be $- 21 + 7^{2}$
$= 28$

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