Question

The sum of $a^2$ and $c{b}^3$ equals the sum of twice to $d$ and thrice to $c$ . Express $b$ in terms of $a,$ $c$ and $d$ .

Answer 1

Given,

$a^2+c{b}^3=2d+3c$

$c{b}^3=2d+3c-a^2$

$b^3=\frac{2d+3c-a^2}{c}$

$b^3=\frac{2d+3c-a^2}{c}$

$b=\sqrt[3]{3\frac{2d+3c-a^2}{c}}$

Hence, this is the answer.