The sum of a + b + 3 and 2a - b - 2 is
6a2−13a+6=?(a) (2a+3)(3a−2)(b) (2a−3)(3a+2)(c) (3a−2)(2a−3)(d) (3a+1)(2a−3)
From the sum of 7a – 2b + 11 and -2a -5, subtract 7a – b + 4.