Question

The sum of a fraction and its square is $\frac{63}{4}$, the fraction is $\frac{14}{4}$ or $\frac{-18}{4}$

• A. True
• B. False

Answer 1

The correct option is A True

Let the fraction $=x$

$x+x^2=\frac{63}{4}$

$4x+4x^2=63$

$4x^2+4x-63=0$

$x=\frac{-4\pm \sqrt{16+16\left(63\right)}}{8}$

$=\frac{-4\pm 32}{8}=\frac{28}{8},\frac{-36}{8}$

$x=\frac{14}{4},\frac{-18}{4}$