Question

The sum of a number and $2$is $6$less than twice that number. Find the number.

Answer 1

Find the required number

Let the number be $x$

From the given condition,

$(x+2)=2x-6$

$$\begin{gathered} \Rightarrow 2x-(x+2)=6 \\ \Rightarrow 2x-x-2=6 \\ \Rightarrow x-2=6 \end{gathered}$$

Adding $2$ to both sides of the equation, we get

$$\begin{gathered} \Rightarrow x-2+2=6+2 \\ \Rightarrow x=8 \end{gathered}$$

Hence, the required number is $8$