Question

The sum of a two-digit number and the number obtained by reversing its digits is $176$. The sum of the digits is $16$, what is the number

Answer 1

Let the two-digit number be $N=10a+b$

The number obtained by reversing the digits is $10b+a$

Given that,

$10a+b+10b+a=176$

$\Rightarrow 11a+11b=176$

$\Rightarrow 11(a+b)=176$

$\Rightarrow a+b=16$

With no other condition given, we cannot exactly find out a single number. But we can now list all numbers which obey the above constraints.

i.e. $88,97,79$