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Byju's Answer
Standard VIII
Mathematics
Numbers in General Form
The sum of a ...
Question
The sum of a two-digit number and the number obtained by reversing its digits is
99
and if digits differ by 3.Find the number.
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Solution
We have,
Case (I)-
⇒
1
unit place
=
x
⇒
10
unit place
=
y
∴
10
y
+
x
Case (II)
10
units place
=
x
1
unit place
=
y
∴
y
+
10
x
10
y
+
x
+
y
+
10
x
=
99
11
y
+
11
x
=
99
11
(
y
+
x
)
=
99
−
−
−
(
I
)
x
+
y
=
9
∴
x
−
y
=
3
−
−
−
−
(
I
I
)
put the value
(
i
)
−
(
i
i
)
2
x
=
12
⇒
x
=
6
∴
sum of two-digit number
36
or
63
Hence this is the answer.
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Q.
The sum of a two digit number and the number obtained by reversing the order of its digits is 99. If the digits differ by 3, find the number.